3x-2y+2z=3,2x+y-3z=11,x+y+z=12
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3x-2y+2z=3,2x+y-3z=11,x+y+z=12
![3x-2y+2z=3,2x+y-3z=11,x+y+z=12](/uploads/image/z/19849085-53-5.jpg?t=3x-2y%2B2z%3D3%2C2x%2By-3z%3D11%2Cx%2By%2Bz%3D12)
x=13/3
y=19/3
z=4/3
再问: 具体过程
再答: 3x-2y+2z=3 (1) 2x+y-3z=11 (2) x+y+z=12 (3) (2)+(3)得 3x+2y-2z=23 (4) (1)+(4)得6x=26 x=13/3 将x代入(3)得y+z=23/3 (5) 将x代入(1)得y-z=5 (6) 解(5)(6)方程组得y=19/3 z=4/3 所以x=13/3 y=19/3 z=4/3
y=19/3
z=4/3
再问: 具体过程
再答: 3x-2y+2z=3 (1) 2x+y-3z=11 (2) x+y+z=12 (3) (2)+(3)得 3x+2y-2z=23 (4) (1)+(4)得6x=26 x=13/3 将x代入(3)得y+z=23/3 (5) 将x代入(1)得y-z=5 (6) 解(5)(6)方程组得y=19/3 z=4/3 所以x=13/3 y=19/3 z=4/3
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x/2=y/3=z/5 x+3y-z/x-3y+z
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
3x-y+z=3 2x+y-3z=11 x+y+z=12 解方程
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6
x+2y+3z=14 2x+y+z=7 3x+y+2z=11
3x+2y+z=9,x+y+2z=0,2x+3y-z=11
2x+3y+z=11,3x+y-z=2,x+y+z=6求解
x+2y+4z=17 2x+y+z=7 3x+y+2z=11
解方程组{2x+3y+z=11,x+y+z=0,3x-y+z=-2.