若cosθ=-5/13,且θ∈(π/2.π),求sin(π-θ)+cos(-θ)的值
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/07 12:56:44
若cosθ=-5/13,且θ∈(π/2.π),求sin(π-θ)+cos(-θ)的值
![若cosθ=-5/13,且θ∈(π/2.π),求sin(π-θ)+cos(-θ)的值](/uploads/image/z/19837192-40-2.jpg?t=%E8%8B%A5cos%CE%B8%3D-5%2F13%2C%E4%B8%94%CE%B8%E2%88%88%28%CF%80%2F2.%CF%80%29%2C%E6%B1%82sin%28%CF%80-%CE%B8%29%2Bcos%28-%CE%B8%29%E7%9A%84%E5%80%BC)
sinθ=12/13
sin(π-θ)+cos(-θ)=sinθ+cosθ=12/13-5/13=7/13
sin(π-θ)+cos(-θ)=sinθ+cosθ=12/13-5/13=7/13
已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小
已知θ∈(-π/2,0),cosθ=13,求sinθ+cos(θ-π/4)的值
已知θ∈(0,π/2)且满足关系logtanθ cosθ=3/2 求logcsc^2θ(sinθ*cosθ)的值.
已知θ∈(0,π/2),且满足关系logtanθCOSθ=2/3,求logcsc^2θ(sinθ*cosθ)的值
已知θ∈(0,π/2),且满足关系logtanθCOSθ=3/2 求logcsc^2θ(sinθ*cosθ)的值.
已知锐角θ满足sin(πcosθ)=cos(πsinθ) 求sin2θ的值?
已知向量m=(Cosθ,Sinθ)和n(根号2 -Sinθ,Cosθ),且Im+nl= 求Cos(θ/2+π/8)
已知sin(θ+kπ)=2cos[θ+(k+1)π],k∈Ζ,求4sinθ-2cosθ/5cosθ+3sinθ的值
已知sinθ+cosθ=1/5,且π/2≤θ≤3π/4,则cos^2-θsin^2θ的值
①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin(
已知向量m=(cosθ,-sinθ),n=(根号2+sinθ,cosθ),θ∈(π,3π/2),且cos(θ/2+π/8