1/(x^2+x-2)-1/(x^2+7x+10)=2的解答过程
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1/(x^2+x-2)-1/(x^2+7x+10)=2的解答过程
帮忙解答啊!
帮忙解答啊!
![1/(x^2+x-2)-1/(x^2+7x+10)=2的解答过程](/uploads/image/z/19809119-47-9.jpg?t=1%2F%28x%5E2%2Bx-2%29-1%2F%28x%5E2%2B7x%2B10%29%3D2%E7%9A%84%E8%A7%A3%E7%AD%94%E8%BF%87%E7%A8%8B)
x^2+x-2 = ( x - 1)(2 + x)
x^2+7x+10 = (2 + x) (5 + x)
1/(x^2+x-2)-1/(x^2+7x+10) = 2
(5 + x) - ( x - 1) = 2( x - 1)((2 + x) (5 + x)
6 = 2( x - 1)((2 + x) (5 + x)
3 = ( x - 1)((2 + x) (5 + x)
x = -4.81691,x = -2.33761,x = 1.15452
x^2+7x+10 = (2 + x) (5 + x)
1/(x^2+x-2)-1/(x^2+7x+10) = 2
(5 + x) - ( x - 1) = 2( x - 1)((2 + x) (5 + x)
6 = 2( x - 1)((2 + x) (5 + x)
3 = ( x - 1)((2 + x) (5 + x)
x = -4.81691,x = -2.33761,x = 1.15452
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