5cos^2(a/2)+6sin(a/2)*cos(a/2)-3sin^2(a/2)-1
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/29 16:48:33
5cos^2(a/2)+6sin(a/2)*cos(a/2)-3sin^2(a/2)-1
(√3tan70+1)/【(4cos²70-2)sin70】
(√3tan70+1)/【(4cos²70-2)sin70】
![5cos^2(a/2)+6sin(a/2)*cos(a/2)-3sin^2(a/2)-1](/uploads/image/z/19763941-13-1.jpg?t=5cos%5E2%28a%2F2%29%2B6sin%28a%2F2%29%2Acos%28a%2F2%29-3sin%5E2%28a%2F2%29-1)
原式=5(1+cosa)/2+3sina-3(1-cosa)/2-1
=3sina+4cosa
=5sin(a+b)
其中tanb=4/3
=3sina+4cosa
=5sin(a+b)
其中tanb=4/3
证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a
化简Sin A + Sin 2A / 1+cos A +
已知 sin a-cos a=1/2,则 sin^3 a-cos^3 a
化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)==
已知(4sin a-2cos a)/(5cos a +3sin a)=6/11,求cos^4 a-sin^4 a
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
已知tan a=-1/3,求4sin a-2cos a/5cos a+3sin a=
【1】化简:sin(a-5π)/cos(3π-a)×cos(π/2-a)/sin(a-3π)×cos(8π-a)/sin
已知2cos∧2 a+3cos a sin a-3sin∧2 a=1,求:tan a,(2sin a-3cos a)\(
已知 sin a,sin 2x ,cos a 成等差数列,sin a ,sin x ,cos a 成等比数列,求cos
求证:tan a/2=(1-cos)/sin a=sin a/(cos a+1)
tan a/2=sin/1+cos a=1-cos a/sin a