求值【sin(2π-α)sin(π+α)cos(-π-α)】/【sin(3π-α)-cos(π-α)】
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求值【sin(2π-α)sin(π+α)cos(-π-α)】/【sin(3π-α)-cos(π-α)】
![求值【sin(2π-α)sin(π+α)cos(-π-α)】/【sin(3π-α)-cos(π-α)】](/uploads/image/z/19738368-0-8.jpg?t=%E6%B1%82%E5%80%BC%E3%80%90sin%282%CF%80-%CE%B1%29sin%28%CF%80%2B%CE%B1%29cos%28-%CF%80-%CE%B1%29%E3%80%91%2F%E3%80%90sin%283%CF%80-%CE%B1%29-cos%28%CF%80-%CE%B1%29%E3%80%91)
sin(2π-α)=-sinα,sin(π+α)=-sinα,cos(-π-α)=-cosα,sin(3π-α)=sinα,cos(π-α)=-cosα
上式=-sinα*sinα*cosα/(sinα+cosα)
就是这样了吧
上式=-sinα*sinα*cosα/(sinα+cosα)
就是这样了吧
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