sin2x+根号3cos2x 怎么样变成2sin(2x+π/3)
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sin2x+根号3cos2x 怎么样变成2sin(2x+π/3)
![sin2x+根号3cos2x 怎么样变成2sin(2x+π/3)](/uploads/image/z/19722805-61-5.jpg?t=sin2x%2B%E6%A0%B9%E5%8F%B73cos2x+%E6%80%8E%E4%B9%88%E6%A0%B7%E5%8F%98%E6%88%902sin%EF%BC%882x%2B%CF%80%2F3%EF%BC%89)
sin2x+√3cos2x
=2(1/2sin2x+√3/2cos2x)
=2(sin2xcosπ/3+cos2xsinπ/3)
=2sin(2x+π/3) 则公式sin(a+b)=sinacosb+cosasinb逆来的.
=2(1/2sin2x+√3/2cos2x)
=2(sin2xcosπ/3+cos2xsinπ/3)
=2sin(2x+π/3) 则公式sin(a+b)=sinacosb+cosasinb逆来的.
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