(sin10°+cos50°)/(cos10°-sin50°)?
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/03 19:47:24
(sin10°+cos50°)/(cos10°-sin50°)?
sin10°+cos50°
=sin10°+sin40°
=2sin25cos15
cos10°-sin50
=sin80-sin50
=2cos65sin15
=2sin25sin15
(sin10°+cos50°)/(cos10°-sin50°)
=2sin25cos15/2sin25sin15
=ctg15
=1/tan15
=1/tg(45-30)
=(1+tan45tan30)/(tan45-tan30)
=2+√3
=sin10°+sin40°
=2sin25cos15
cos10°-sin50
=sin80-sin50
=2cos65sin15
=2sin25sin15
(sin10°+cos50°)/(cos10°-sin50°)
=2sin25cos15/2sin25sin15
=ctg15
=1/tan15
=1/tg(45-30)
=(1+tan45tan30)/(tan45-tan30)
=2+√3
计算1sin50°+3cos50°
求值:2sin50°+cos10°*(1+根号3tan10°)/cs35°cos40°+cos50°cos55°
化简求值2sin50°+cos10°(1+3tan10°)cos35°cos40°+cos50°cos55°
sin40°cos10°-SIN10°SIN50°的值是
2sin50°cos50°怎么等于cos50°cos40°+sin50°sin40°
计算sin50°cos40°+cos50°sin40°
sin50°*cos40°+cos50°*sin40°
sin50°=a cos40°=?cos50°?
cos20°cos10°+sin10°sin10°
化简sin10°-根号3*cos10°
sin10°sin50°-sin50°sin70°-sin70°sin10°=?
计算 sin10°^2 + sin50°^2 + sin10°sin50° 的值? 答案:3/4