函数f(x)对任何x>0恒有f(x1)+f(x2)=f(x1x2),若f(8)=3,则f(根号2)=?
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:综合作业 时间:2024/08/12 11:33:40
函数f(x)对任何x>0恒有f(x1)+f(x2)=f(x1x2),若f(8)=3,则f(根号2)=?
![函数f(x)对任何x>0恒有f(x1)+f(x2)=f(x1x2),若f(8)=3,则f(根号2)=?](/uploads/image/z/19624594-58-4.jpg?t=%E5%87%BD%E6%95%B0f%28x%29%E5%AF%B9%E4%BB%BB%E4%BD%95x%3E0%E6%81%92%E6%9C%89f%28x1%29%2Bf%28x2%29%3Df%28x1x2%29%2C%E8%8B%A5f%288%29%3D3%2C%E5%88%99f%28%E6%A0%B9%E5%8F%B72%29%3D%3F)
f(x1)+f(x2)=f(x1x2)
f(8)=f(2*4)=f(2)+f(4)=f(2)+f(2*2)=f(2)+f(2)+f(2)=3*f(2)=3
f(2)=1
f(2)=f(√2*√2)f(√2)+f(√2)=2*f(√2)=1
f(√2)=1/2
f(8)=f(2*4)=f(2)+f(4)=f(2)+f(2*2)=f(2)+f(2)+f(2)=3*f(2)=3
f(2)=1
f(2)=f(√2*√2)f(√2)+f(√2)=2*f(√2)=1
f(√2)=1/2
函数f(x)对任何x属于R+恒有f(x1*x2)=f(x1)+f(x2),已知f(8)=3,则f(根号2)=
已知函数f(x)对任意实数x1,x2都有f(x1x2)=f(x1)+f(x2)成立,则f(0)=?f(1)=?
设函数f(x)定义域(0,+∞),且f(4)=1,对任意正实数x1x2,有f(x1x2)=f(x1)+f(x2),且当x
已知f(x)是定义在(0,+∝)上的增函数,f(2)=1,f(x1x2)=f(x1)+f(x2)对x1,x2属于(0,+
已知偶函数f(x),对任意x1,x2∈R,恒有:f(x1+x2)=f(x1)+f(x2)+2x1x2+1.
设函数f(x)的定义域为R,若f(π/2)=0,f(π)=-1,且对任意的X1X2有f(X1)+f(X2)=2f(X1+
函数f(x)对一切x属于R^+,恒有f(x1,x2)=f(x1)+f(x2),若f(8)=3,则f(2^1/2)=?
设函数f(x)对任何实数x1,x2有f(x1+x2)=f(x1)f(x2)且f`(0)=1,证明f`(x)=f(x)
已知函数f(x)对任意实数x1,x2都有f(x1x2)=f(x1)+f(x2)成立,则f(0)=______,f(1)=
函数f(x),x∈R,若对于任意实数x1,x2都有f(x1+x2)+f(x1-x2)=2f(x1).f(x2),求证f(
已知函数f(x)(x∈R,x≠0)对任意的非零实数x1,x2,恒有f(x1x2)=f(x1)+f(x2),且当X>1,f
已知函数y=f (x)(x∈R,x≠0)对任意的非零实数x1,x2,恒有f(x1x2)=f(x1)+f(x2),试判断f