2个等差数列{An}、{Bn}的前n项和之比为5n+3/2n-1.则A10/B10=多少?
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2个等差数列{An}、{Bn}的前n项和之比为5n+3/2n-1.则A10/B10=多少?
详细解答
详细解答
![2个等差数列{An}、{Bn}的前n项和之比为5n+3/2n-1.则A10/B10=多少?](/uploads/image/z/19578017-65-7.jpg?t=2%E4%B8%AA%E7%AD%89%E5%B7%AE%E6%95%B0%E5%88%97%7BAn%7D%E3%80%81%7BBn%7D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8C%E4%B9%8B%E6%AF%94%E4%B8%BA5n%2B3%2F2n-1.%E5%88%99A10%2FB10%3D%E5%A4%9A%E5%B0%91%3F)
设5n+3/2n-1=t
则前10项和比为53/19
前9项和比为48/17
A10/B10=(53t-48t)/(19t-17t)=5/2
则前10项和比为53/19
前9项和比为48/17
A10/B10=(53t-48t)/(19t-17t)=5/2
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