x+2y-3z=0,5x-6y+7z=0,则x∶y∶z=____.
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x+2y-3z=0,5x-6y+7z=0,则x∶y∶z=____.
![x+2y-3z=0,5x-6y+7z=0,则x∶y∶z=____.](/uploads/image/z/19549735-7-5.jpg?t=x%2B2y-3z%3D0%2C5x-6y%2B7z%3D0%2C%E5%88%99x%E2%88%B6y%E2%88%B6z%3D____.)
消元~令两个式子为(1)(2)
(1)*3,为3x+6y-9z=0(3),(3)+(2)=8x-2z=0,所以x:z=1:4(5)
(1)*5,为5x+10y-15z=0(4),(4)-(2)=16y-22z=0,所以y:z=11:8(6)
(5)*2=2:8,(6)为y:z=11:8,所以x:y:z=2:11:8
(1)*3,为3x+6y-9z=0(3),(3)+(2)=8x-2z=0,所以x:z=1:4(5)
(1)*5,为5x+10y-15z=0(4),(4)-(2)=16y-22z=0,所以y:z=11:8(6)
(5)*2=2:8,(6)为y:z=11:8,所以x:y:z=2:11:8
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