2x/x-1+1/x+3-3x+5/x^2+2x-3计算,
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2x/x-1+1/x+3-3x+5/x^2+2x-3计算,
![2x/x-1+1/x+3-3x+5/x^2+2x-3计算,](/uploads/image/z/19514560-40-0.jpg?t=2x%2Fx-1%2B1%2Fx%2B3-3x%2B5%2Fx%5E2%2B2x-3%E8%AE%A1%E7%AE%97%2C)
=2x/(x-1)+1/(x+3)-(3x+5)/(x+3)(x-1)
=[2x(x+3)+(x-1)-(3x+5)]/(x+3)(x-1)
=(2x²+6x+x-1-3x-5)/(x+3)(x-1)
=(2x²+4x-6)/(x²+2x-3)
=2
=[2x(x+3)+(x-1)-(3x+5)]/(x+3)(x-1)
=(2x²+6x+x-1-3x-5)/(x+3)(x-1)
=(2x²+4x-6)/(x²+2x-3)
=2
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