tan(π/8)+1/(tan(π/12))值,要过程
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tan(π/8)+1/(tan(π/12))值,要过程
![tan(π/8)+1/(tan(π/12))值,要过程](/uploads/image/z/19471035-3-5.jpg?t=tan%28%CF%80%2F8%29%2B1%2F%28tan%28%CF%80%2F12%29%29%E5%80%BC%2C%E8%A6%81%E8%BF%87%E7%A8%8B)
tan(π/4)=2tan(π/8)/(1-tan(π/8)^2)=1
tan(π/6)=2tan(π/12)/(1-tan(π/12)^2)=(根号3)/3
解二次方程
因为tan(π/8),tan(π/12)>0
求根公式取正
tan(π/8)=(根号2)-1
tan(π/12)=2-根号3
所以原式=(根号2)-1+1/(2-根号3)
=(根号2)-1+2+根号3
=根号3+根号2+1
tan(π/6)=2tan(π/12)/(1-tan(π/12)^2)=(根号3)/3
解二次方程
因为tan(π/8),tan(π/12)>0
求根公式取正
tan(π/8)=(根号2)-1
tan(π/12)=2-根号3
所以原式=(根号2)-1+1/(2-根号3)
=(根号2)-1+2+根号3
=根号3+根号2+1
化简:tan(π/8)+1/tan(π/12)
tan(π/12)+1/tan(π/12)=啥?
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