log√2 9 *log27 32
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log√2 9 *log27 32
![log√2 9 *log27 32](/uploads/image/z/19450959-15-9.jpg?t=log%E2%88%9A2+9+%2Alog27+32)
解
=[log 9/log√2]*[log32/log27 ]
=[log 9/log27]*[log32/log √2]
=[2/3]*[5/(1/2)]
=20/3
=[log 9/log√2]*[log32/log27 ]
=[log 9/log27]*[log32/log √2]
=[2/3]*[5/(1/2)]
=20/3
关于log的计算log8(9)* log27 (32)log4 (3) *log9(2)- log 1/2(四倍根号下3
计算:log27(32)×log64(27)+log9(2)×log4(√27)=
log(3)2-log(3)32/9+log(3)16 - 5的2log(5)3次方
求log₂25×log₃2√2×log(5)9的结果,
-5log⑨4+log③32/9-5^log⑤3-(1/64)^-2/3
log(2)(25)*log(3)(根号2)*log(5)(9)
log(2)9×log(3)4
log(2)9log(3)4等于
log8^9.log27^32+lg25+lg2.lg50+lg2.lg2
log25(底数)9(真数)×log27(底数)625(真数)=?
用换底公式简化[log(4)3+log(8)3][log(3)2+log(9)2]
(log(4)3+log(8)3)(log(3)2+log(9)2) 怎么个思路