求证(sin2a+1)/(1+cos2a+sin2a)=1/2tana+1/2
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求证(sin2a+1)/(1+cos2a+sin2a)=1/2tana+1/2
![求证(sin2a+1)/(1+cos2a+sin2a)=1/2tana+1/2](/uploads/image/z/19412823-39-3.jpg?t=%E6%B1%82%E8%AF%81%EF%BC%88sin2a%2B1%EF%BC%89%2F%EF%BC%881%2Bcos2a%2Bsin2a%EF%BC%89%3D1%2F2tana%2B1%2F2)
如图所示(图片需要审核,稍等一下)
![](http://img.wesiedu.com/upload/9/9c/99c2cd39a591bb6c8aad778258eea446.jpg)
![](http://img.wesiedu.com/upload/9/9c/99c2cd39a591bb6c8aad778258eea446.jpg)
求证:2(sin2a+1)/(1+sin2a+cos2a)=tana+1
求证:1+sin2a-cos2a/1+sin2a+cos2a=tana
求证1+sin2a-cos2a除以1+sin2a+cos2a=tana
证明 2(sin2a+1)/1+sin2a+cos2a=tana+1
(sin2a-cos2a)^2=1-sin4a 求证!
1.化简[2sin2a/(1+cos2a)]*1/tana
求证:1+sin2a/cos2a=1+tana/1-tana
已知2sin2a+1=cos2a,求tana的值
半角公式sin2a=2tana^2/(1+tana^2) cos2a=(1-tana^2)/(1+tana^2) tan
证明:(sin2a+1)/(sin2a+cos2a+1)=1/2(tana+1)
化简sin2a(1+tana*tana/2)
1+sin2a-cos2a/1+sin2a+cos2a为什么等于tana?