已知x/2=y/7=z/3设A=y/(x+y+z)B=(x+z)/yC=(x+y-z)/x那么ABC大小顺序为
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已知x/2=y/7=z/3设A=y/(x+y+z)B=(x+z)/yC=(x+y-z)/x那么ABC大小顺序为
![已知x/2=y/7=z/3设A=y/(x+y+z)B=(x+z)/yC=(x+y-z)/x那么ABC大小顺序为](/uploads/image/z/19395813-21-3.jpg?t=%E5%B7%B2%E7%9F%A5x%2F2%3Dy%2F7%3Dz%2F3%E8%AE%BEA%3Dy%2F%28x%2By%2Bz%29B%3D%28x%2Bz%29%2FyC%3D%28x%2By-z%29%2Fx%E9%82%A3%E4%B9%88ABC%E5%A4%A7%E5%B0%8F%E9%A1%BA%E5%BA%8F%E4%B8%BA)
设x/2=y/7=z/3=k
x=2k,y=7k,z=3k
A=y/(x+y+z)=7k/(2k+7k+3k)=7/12
B=(x+z)/y=(2k+3k)/7k=5/7
C=(x+y-z)/x=(2k+7k-3k)/2k=3
C>B>A
x=2k,y=7k,z=3k
A=y/(x+y+z)=7k/(2k+7k+3k)=7/12
B=(x+z)/y=(2k+3k)/7k=5/7
C=(x+y-z)/x=(2k+7k-3k)/2k=3
C>B>A
(x+y-z)(x-y+z)=
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