如图,在△ABD和△ACE,AE=AB,AD=AC,∠EAB=∠DAC,BD和CE交于点O,求证:AO平分∠EOD
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如图,在△ABD和△ACE,AE=AB,AD=AC,∠EAB=∠DAC,BD和CE交于点O,求证:AO平分∠EOD
![](http://img.wesiedu.com/upload/e/63/e63b7561c7169f047716e783642a9d3e.jpg)
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![如图,在△ABD和△ACE,AE=AB,AD=AC,∠EAB=∠DAC,BD和CE交于点O,求证:AO平分∠EOD](/uploads/image/z/19332982-46-2.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABD%E5%92%8C%E2%96%B3ACE%2CAE%3DAB%2CAD%3DAC%2C%E2%88%A0EAB%3D%E2%88%A0DAC%2CBD%E5%92%8CCE%E4%BA%A4%E4%BA%8E%E7%82%B9O%2C%E6%B1%82%E8%AF%81%EF%BC%9AAO%E5%B9%B3%E5%88%86%E2%88%A0EOD)
证明:过点A作AM⊥EC于M,AN⊥BD于N
∵∠EAC=∠EAB+∠BAC,∠BAD=∠DAC+∠BAC,∠EAC=∠DAC
∴∠EAC=∠BAD
∵AE=AB,AD=AC
∴△AEC≌△ABD (SAS)
∴EC=BD,S△AEC=S△ABD
∵AM⊥EC,AN⊥BD
∴S△AEC=EC×AM/2,S△ABD=BD×AN/2
∴EC×AM/2=BD×AN/2
∴AM=AN
∴AO平分∠EOD
数学辅导团解答了你的提问,
∵∠EAC=∠EAB+∠BAC,∠BAD=∠DAC+∠BAC,∠EAC=∠DAC
∴∠EAC=∠BAD
∵AE=AB,AD=AC
∴△AEC≌△ABD (SAS)
∴EC=BD,S△AEC=S△ABD
∵AM⊥EC,AN⊥BD
∴S△AEC=EC×AM/2,S△ABD=BD×AN/2
∴EC×AM/2=BD×AN/2
∴AM=AN
∴AO平分∠EOD
数学辅导团解答了你的提问,
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