log3 72-3log3 2 怎么化简
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log3 72-3log3 2 怎么化简
![log3 72-3log3 2 怎么化简](/uploads/image/z/19323516-12-6.jpg?t=log3+72-3log3+2+%E6%80%8E%E4%B9%88%E5%8C%96%E7%AE%80)
log3 72-3log3 2
=log3 72-log3 2³
=log3 72-log3 8
=log3 (72/8)
=log3 9
=log3 3²
=2log3 3
=2
=log3 72-log3 2³
=log3 72-log3 8
=log3 (72/8)
=log3 9
=log3 3²
=2log3 3
=2
log3/2乘以5log2/3怎么化简?
log2(3)+log3(5)+log3(2)=?
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2)
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
一道对数计算,log3(27/5)+log3(2/3)-log3(6/5)
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解不等式(2+log3 x)log3 x>log3 (9x)
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设a=log3π,b=log3根号3,c=log3根号2比较abc