设f(θ)=2cos³-sin²(θ+π)-2cos(-θ-π)+1/2+2cos²(7π
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设f(θ)=2cos³-sin²(θ+π)-2cos(-θ-π)+1/2+2cos²(7π+θ)+cos(-θ),求f(π/3)
![设f(θ)=2cos³-sin²(θ+π)-2cos(-θ-π)+1/2+2cos²(7π](/uploads/image/z/19323174-30-4.jpg?t=%E8%AE%BEf%28%CE%B8%29%3D2cos%26%23179%3B-sin%26%23178%3B%28%CE%B8%2B%CF%80%29-2cos%28-%CE%B8-%CF%80%29%2B1%2F2%2B2cos%26%23178%3B%EF%BC%887%CF%80)
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