sin(x-20°)+cos(x+70°)+sin(x+20°)sec(70-x)=?
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sin(x-20°)+cos(x+70°)+sin(x+20°)sec(70-x)=?
请问有何简便解法?
请问有何简便解法?
![sin(x-20°)+cos(x+70°)+sin(x+20°)sec(70-x)=?](/uploads/image/z/19310760-0-0.jpg?t=sin%28x-20%C2%B0%29%2Bcos%28x%2B70%C2%B0%29%2Bsin%28x%2B20%C2%B0%29sec%2870-x%29%3D%3F)
sin(x-20°)+cos(x+70°)+sin(x+20°)sec(70-x)
=sin(x-20°)+sin(20°-x)+sin(x-20°)/cos(70°-x)
=sin(x-20°)-sin(x-20°)+sin(x-20°)/sin(x-20°)
=0+1
=1
=sin(x-20°)+sin(20°-x)+sin(x-20°)/cos(70°-x)
=sin(x-20°)-sin(x-20°)+sin(x-20°)/sin(x-20°)
=0+1
=1
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