x2;+y2+6x-4y+13=0 求(x+y)2008
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x2;+y2+6x-4y+13=0 求(x+y)2008
![x2;+y2+6x-4y+13=0 求(x+y)2008](/uploads/image/z/19298139-51-9.jpg?t=x2%3B%2By2%2B6x-4y%2B13%3D0+%E6%B1%82%28x%2By%292008)
x2+y2+6x-4y+13
=(x+3)^2+(y-2)^2
=0
x+3=0,y-2=0
x=-3,y=2
(x+y)^2008=(-3+2)^2008=1
=(x+3)^2+(y-2)^2
=0
x+3=0,y-2=0
x=-3,y=2
(x+y)^2008=(-3+2)^2008=1
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