设bn=1/2*3/4*5/6*...*(2n-1)/(2n) ,求证:b1+b2+...+bn
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设bn=1/2*3/4*5/6*...*(2n-1)/(2n) ,求证:b1+b2+...+bn
![设bn=1/2*3/4*5/6*...*(2n-1)/(2n) ,求证:b1+b2+...+bn](/uploads/image/z/19269587-11-7.jpg?t=%E8%AE%BEbn%3D1%2F2%2A3%2F4%2A5%2F6%2A...%2A%282n-1%29%2F%282n%29+%2C%E6%B1%82%E8%AF%81%3Ab1%2Bb2%2B...%2Bbn)
(2n-1)/(2n) < (2n-1)/根号下(4n^2-1)=根号下((2n-1)/(2n+1))
将这些式子全部相乘,即得证
将这些式子全部相乘,即得证
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