1/x(x-1)+1/x(x+1)+1/(x+1)(x+20.+1/(x+9)(x+10)=11/12
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1/x(x-1)+1/x(x+1)+1/(x+1)(x+20.+1/(x+9)(x+10)=11/12
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知道的回答!
![1/x(x-1)+1/x(x+1)+1/(x+1)(x+20.+1/(x+9)(x+10)=11/12](/uploads/image/z/19257978-66-8.jpg?t=1%2Fx%28x-1%29%2B1%2Fx%28x%2B1%29%2B1%2F%28x%2B1%29%28x%2B20.%2B1%2F%28x%2B9%29%28x%2B10%29%3D11%2F12)
原式=1/[x-1]-1/x+1/x-1/[x+1]+1/[x+1]-1/[x+2]+...+1/[x+9]-1/[x+10]=11/12
1/[x-1]-1/[x+10]=11/12
11/[x-1][x+10]=11/12
[x-1][x+10]=12
x=2或x= -11
1/[x-1]-1/[x+10]=11/12
11/[x-1][x+10]=11/12
[x-1][x+10]=12
x=2或x= -11
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解方程:x(x-1)/1+x(x+1)/1…+(x+9)(x+10)/1=11?12