如果(1-tanx)/(1+tanx)=4+√5 则tan(π/4+x)=?
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如果(1-tanx)/(1+tanx)=4+√5 则tan(π/4+x)=?
![如果(1-tanx)/(1+tanx)=4+√5 则tan(π/4+x)=?](/uploads/image/z/19222924-4-4.jpg?t=%E5%A6%82%E6%9E%9C%281-tanx%29%2F%281%2Btanx%29%3D4%2B%E2%88%9A5+%E5%88%99tan%28%CF%80%2F4%2Bx%29%3D%3F)
tan(π/4+x)=sin(x+π/4)/cos(x+π/4)=sin(x+π/4)/sin(π/4-x)=sin(x+π/4)/(-sin(x-π/4))=(sinx+cosx)/(cosx-sinx)=(tanx+1)/(1-tanx)=1/(4+√5)=(4-√5)/11
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