(2x+y)²-(x+2y)²
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(2x+y)²-(x+2y)²
![(2x+y)²-(x+2y)²](/uploads/image/z/19199282-50-2.jpg?t=%EF%BC%882x%2By%EF%BC%89%26%23178%3B-%28x%2B2y%29%26%23178%3B)
平方差
原式=(2x+y+x+3y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
原式=(2x+y+x+3y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
(x-2y)²+(2x-4y)(x+y)+(x+y)²
(x-y)的四次方(x-y)-2(x-y)²(y-x)³等于?
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(3x-y)²-2x(4x-5y)-(x+2y)²
{(x-y)²+(x+y)(x-y)}÷2x
先化简再求值:(x-2y)²-(x+2y)(x-2y)-(x-3y)(x-y).其中x²+9y
先化简,在求值:(x-y)²+(3x-2y)(2x+y)-x(6x-y)
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
(2x+y)²-(x+2y)² 因式分解