化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/02 02:56:13
化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)
![化简:(sin^2α-tan^2α)/(sin^2α·tan^2α)](/uploads/image/z/19106260-52-0.jpg?t=%E5%8C%96%E7%AE%80%EF%BC%9A%28sin%5E2%CE%B1-tan%5E2%CE%B1%29%2F%28sin%5E2%CE%B1%C2%B7tan%5E2%CE%B1%29)
(sin²α-tan²α)/(sin²α·tan²α)
=(sin²α-sin²α/cos²α)/(sin²α·sin²α/cos²α)
=(sin²α*cos²α-sin²α)/(sin²α·sin²α)
=(cos²α-1)/sin²α
=-sin²α/sin²α
=-1
=(sin²α-sin²α/cos²α)/(sin²α·sin²α/cos²α)
=(sin²α*cos²α-sin²α)/(sin²α·sin²α)
=(cos²α-1)/sin²α
=-sin²α/sin²α
=-1
已知tanα=2,sinα
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