若2x2+2xy+y2-2x+1=0,则xy的值是______.
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若2x2+2xy+y2-2x+1=0,则xy的值是______.
![若2x2+2xy+y2-2x+1=0,则xy的值是______.](/uploads/image/z/19106164-28-4.jpg?t=%E8%8B%A52x2%2B2xy%2By2-2x%2B1%3D0%EF%BC%8C%E5%88%99xy%E7%9A%84%E5%80%BC%E6%98%AF______%EF%BC%8E)
∵2x2+2xy+y2-2x+1=0,即(x+y)2+(x-1)2=0,
∴
x+y=0
x−1=0,解得
x=1
y=−1.
∴xy=1×(-1)=-1.
∴
x+y=0
x−1=0,解得
x=1
y=−1.
∴xy=1×(-1)=-1.
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