(1/6)×(2X-3)²=36 (5X-2)²=-125 怎么算?
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(1/6)×(2X-3)²=36 (5X-2)²=-125 怎么算?
![(1/6)×(2X-3)²=36 (5X-2)²=-125 怎么算?](/uploads/image/z/19041255-63-5.jpg?t=%EF%BC%881%2F6%EF%BC%89%C3%97%EF%BC%882X-3%29%26%23178%3B%3D36+%EF%BC%885X-2%EF%BC%89%26%23178%3B%3D-125+%E6%80%8E%E4%B9%88%E7%AE%97%3F)
两边同乘以6得
(2X-3)²=216
两边同时开平方:2x-3=正负6×根号6
解得:x1=(3+ 6×根号6)/2,x2=(3- 6×根号6)/2
5X-2)²大于等于0 而-125
(2X-3)²=216
两边同时开平方:2x-3=正负6×根号6
解得:x1=(3+ 6×根号6)/2,x2=(3- 6×根号6)/2
5X-2)²大于等于0 而-125
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