(2-cosa)/sina 化简成用tan(a/2)代替的怎么化?
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(2-cosa)/sina 化简成用tan(a/2)代替的怎么化?
应该化成 1/2[(1/x +3x)] X=tan(a/2)
应该化成 1/2[(1/x +3x)] X=tan(a/2)
![(2-cosa)/sina 化简成用tan(a/2)代替的怎么化?](/uploads/image/z/19022991-15-1.jpg?t=%282-cosa%29%2Fsina+%E5%8C%96%E7%AE%80%E6%88%90%E7%94%A8tan%28a%2F2%29%E4%BB%A3%E6%9B%BF%E7%9A%84%E6%80%8E%E4%B9%88%E5%8C%96%3F)
cosa=(cos(a/2)^2-sin(a/2)^2)/(cos(a/2)^2+sin(a/2)^2)=(1-x^2)/(1+x^2)
sina=2sin(a/2)cos(a/2)/(sin(a/2)^2+cos(a/2)^2)=2x/(1+x^2)
sina=2sin(a/2)cos(a/2)/(sin(a/2)^2+cos(a/2)^2)=2x/(1+x^2)
已知tan(a+π/4)=-3,则2sina-cosa/sina+cosa的值是多少?怎么算?
证明(1-cos^2a)/(sina+cosa)-(sina+cosa)/(tan^2a-1)=sina+cosa
已知tan(a+∏/4=2,求sina+cosa/cosa-sina的值
tan(a/2)等于sina/(1+cosa)的过程
证明(1-cos^2a)/(sina-cosa)-(sina+cosa)/(tan^2-1)=sina+cosa
求证:1-cos^2a/sina-cosa - sina+cosa/tan^2a-1=sina+cosa
已知tan(A+3兀)=3,求sinA一2cosA/sinA十cosA的值
[(sina+cosa)^2-(sina-cosa)^2]/tana-sinacosa=4/tan^2a 求证
tan a/2=3 1-cosa-sina/1+cosa+sina
证明(1+sinA-cosA)/(1+sinA+cosA)=tan(A/2)
tan(a/2)=sina/(1+cosa)=(1-cosa)/sina
tan(a/2)=sina/(1+cosa) 怎样证明