若x2+4x+y2-6y+13=0则x=?y=?
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若x2+4x+y2-6y+13=0则x=?y=?
![若x2+4x+y2-6y+13=0则x=?y=?](/uploads/image/z/19017461-29-1.jpg?t=%E8%8B%A5x2%2B4x%2By2-6y%2B13%3D0%E5%88%99x%3D%3Fy%3D%3F)
x^2+4x+y^2-6y+13=0
解: (x^2+4x+4)+(y^2-6y+9)=0
(x+2)^2+(y-3)^2=2
因为x+20,y-30;且(x+2)^2+(y-3)^2=0
所以x=-2,y=3
解: (x^2+4x+4)+(y^2-6y+9)=0
(x+2)^2+(y-3)^2=2
因为x+20,y-30;且(x+2)^2+(y-3)^2=0
所以x=-2,y=3
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