一道解三角形的题,
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/11 23:36:36
一道解三角形的题,
![](http://img.wesiedu.com/upload/f/1a/f1aa03bd91c50661fecc6c3b09a0371d.jpg)
![](http://img.wesiedu.com/upload/f/1a/f1aa03bd91c50661fecc6c3b09a0371d.jpg)
![一道解三角形的题,](/uploads/image/z/19011276-36-6.jpg?t=%E4%B8%80%E9%81%93%E8%A7%A3%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E9%A2%98%2C%26nbsp%3B)
acosC+√3asinC-b-c=0
sinAcosC+√3sinAsinC-sinB-sinC=0
sinAcosC+√3sinAsinC-sinAcosC-sinCcosA-sinC=0
√3sinAsinC-sinCcosA-sinC=0
√3sinA-cosA-1=0
2sin(A-π/6)=1
A-π/6=π/6 a=π/3 A-π/6=5π/6 A=π(不符题意)
S=√3=1/2bcsinA bc=4
cosA=(b^2+c^2-a^2)/2bc
(b+c)^2-2bc=2*4*1/2-2^2=0
(b+c)^2=8 无解
sinAcosC+√3sinAsinC-sinB-sinC=0
sinAcosC+√3sinAsinC-sinAcosC-sinCcosA-sinC=0
√3sinAsinC-sinCcosA-sinC=0
√3sinA-cosA-1=0
2sin(A-π/6)=1
A-π/6=π/6 a=π/3 A-π/6=5π/6 A=π(不符题意)
S=√3=1/2bcsinA bc=4
cosA=(b^2+c^2-a^2)/2bc
(b+c)^2-2bc=2*4*1/2-2^2=0
(b+c)^2=8 无解