解方程组(x+2)(y-1)=(x-2)(y+2)和(x-12)(y-14)=(x+12)(y-2)
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解方程组(x+2)(y-1)=(x-2)(y+2)和(x-12)(y-14)=(x+12)(y-2)
(x+2)(y-1)=(x-2)(y+2)
(x-12)(y-14)=(x+12)(y-2)
xy+2y-x-2=xy-2y+2x-4
xy-12y-14x+168=xy+12y-2x-24
3x-4y-2=0
12x+24y-192=0
3x-4y-2=0
x+2y-16=0
{x=34/5
{y23/5
再问: 不好意思我题目打错了(x+2)(y-1)=(x-2)(y+3)和(x-12)(y-14)=(x+12)(y-2)是这个再帮下忙
再答: (x+2)(y-1)=(x-2)(y+3)和 (x-12)(y-14)=(x+12)(y-2) (x+2)(y-1)=(x-2)(y+3) (x-12)(y-14)=(x+12)(y-2) xy+2y-x-2=xy-2y+3x-6 xy-12y-14x+168=xy+12y-2x-24 4x-4y-4=0 12x+24y-192=0 x-y-1=0 x+2y-16=0 下式减上式得: 3y=15 y=5 x=6 所以原式的解为: {x=6 {y=5 答案已验证确认正确!
(x-12)(y-14)=(x+12)(y-2)
xy+2y-x-2=xy-2y+2x-4
xy-12y-14x+168=xy+12y-2x-24
3x-4y-2=0
12x+24y-192=0
3x-4y-2=0
x+2y-16=0
{x=34/5
{y23/5
再问: 不好意思我题目打错了(x+2)(y-1)=(x-2)(y+3)和(x-12)(y-14)=(x+12)(y-2)是这个再帮下忙
再答: (x+2)(y-1)=(x-2)(y+3)和 (x-12)(y-14)=(x+12)(y-2) (x+2)(y-1)=(x-2)(y+3) (x-12)(y-14)=(x+12)(y-2) xy+2y-x-2=xy-2y+3x-6 xy-12y-14x+168=xy+12y-2x-24 4x-4y-4=0 12x+24y-192=0 x-y-1=0 x+2y-16=0 下式减上式得: 3y=15 y=5 x=6 所以原式的解为: {x=6 {y=5 答案已验证确认正确!
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