只有一道题而已!关于分式加减的计算!
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/28 14:54:52
只有一道题而已!关于分式加减的计算!
![](http://img.wesiedu.com/upload/3/32/332a42708b38b0227719bd4ba767fc70.jpg)
![](http://img.wesiedu.com/upload/3/32/332a42708b38b0227719bd4ba767fc70.jpg)
![只有一道题而已!关于分式加减的计算!](/uploads/image/z/18973632-48-2.jpg?t=%E5%8F%AA%E6%9C%89%E4%B8%80%E9%81%93%E9%A2%98%E8%80%8C%E5%B7%B2%21%E5%85%B3%E4%BA%8E%E5%88%86%E5%BC%8F%E5%8A%A0%E5%87%8F%E7%9A%84%E8%AE%A1%E7%AE%97%21)
[1+(2/(x-2)]^2+[1-2/(x-2)]^2=x/(x-2)
1+4/(x-2)+4/(x-2)^2+1-4/(x-2)+4/(x-2)^2=x/(x-2)
2+8/(x-2)^2=x/(x-2)
2(x-2)^2+8-x(x-2)=0
2x^2-8x+16-x^2+2x=0
x^2-6x+16=0
△=36-4×16=-28
1+4/(x-2)+4/(x-2)^2+1-4/(x-2)+4/(x-2)^2=x/(x-2)
2+8/(x-2)^2=x/(x-2)
2(x-2)^2+8-x(x-2)=0
2x^2-8x+16-x^2+2x=0
x^2-6x+16=0
△=36-4×16=-28