分解因式:1-x2-y2+x2y2-4xy=______.
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分解因式:1-x2-y2+x2y2-4xy=______.
![分解因式:1-x2-y2+x2y2-4xy=______.](/uploads/image/z/18903901-13-1.jpg?t=%E5%88%86%E8%A7%A3%E5%9B%A0%E5%BC%8F%EF%BC%9A1-x2-y2%2Bx2y2-4xy%3D______%EF%BC%8E)
1-x2-y2+x2y2-4xy
=(1+x2y2-2xy)-(x2+y2+2xy)
=(1-xy)2-(x+y)2
=(1-xy+x+y)(1-xy-x-y).
故答案为:(1-xy+x+y)(1-xy-x-y).
=(1+x2y2-2xy)-(x2+y2+2xy)
=(1-xy)2-(x+y)2
=(1-xy+x+y)(1-xy-x-y).
故答案为:(1-xy+x+y)(1-xy-x-y).
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