f(x)=2sin(2x+2A+π/6)+1,A为常数,(1)设∠A,∠B是三角形ABC的内角,若f(B)=0,求∠C
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f(x)=2sin(2x+2A+π/6)+1,A为常数,(1)设∠A,∠B是三角形ABC的内角,若f(B)=0,求∠C
![f(x)=2sin(2x+2A+π/6)+1,A为常数,(1)设∠A,∠B是三角形ABC的内角,若f(B)=0,求∠C](/uploads/image/z/18898652-20-2.jpg?t=f%28x%29%3D2sin%282x%2B2A%2B%CF%80%2F6%29%2B1%2CA%E4%B8%BA%E5%B8%B8%E6%95%B0%2C%EF%BC%881%EF%BC%89%E8%AE%BE%E2%88%A0A%2C%E2%88%A0B%E6%98%AF%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E5%86%85%E8%A7%92%2C%E8%8B%A5f%28B%29%3D0%2C%E6%B1%82%E2%88%A0C)
f(B)=2sin(2B+2A+π/6)+1=0
sin(2B+2A+π/6)=-1/2=sin7π/6或sin11π/6
2A+2B+π/6=7π/6或11π/6
A+B=π/2或5π/6
C=π-(A+B)=π/2或π/6
sin(2B+2A+π/6)=-1/2=sin7π/6或sin11π/6
2A+2B+π/6=7π/6或11π/6
A+B=π/2或5π/6
C=π-(A+B)=π/2或π/6
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