1.(8xy-x²+y²)-(x²-y²+8xy)
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1.(8xy-x²+y²)-(x²-y²+8xy)
2.(2x²-1/2+3x)-4(x-x²+1/2)
3.3x²-[7x-(4x-3)-2x²]
2.(2x²-1/2+3x)-4(x-x²+1/2)
3.3x²-[7x-(4x-3)-2x²]
![1.(8xy-x²+y²)-(x²-y²+8xy)](/uploads/image/z/18890804-20-4.jpg?t=1.%288xy-x%26sup2%3B%2By%26sup2%3B%29-%28x%26sup2%3B-y%26sup2%3B%2B8xy%29)
1、(8xy-x²+y²)-(x²-y²+8xy)=[8xy-(x²-y²)][8xy+(x²-y²)]
=64x²y²-(x²-y²)=64x²y²-x^4+2x²y²-y^4=66x²y²-x^4-y^4
2、 (2x²-1/2+3x)-4(x-x²+1/2)= 2x²-1/2+3x-4x+4x²-2
= 6x²-x-2.5
3、3x²-[7x-(4x-3)-2x²]=3x²-7x+(4x-3)+2x²
=5x²-7x+4x-3=5x²-3x-3
=64x²y²-(x²-y²)=64x²y²-x^4+2x²y²-y^4=66x²y²-x^4-y^4
2、 (2x²-1/2+3x)-4(x-x²+1/2)= 2x²-1/2+3x-4x+4x²-2
= 6x²-x-2.5
3、3x²-[7x-(4x-3)-2x²]=3x²-7x+(4x-3)+2x²
=5x²-7x+4x-3=5x²-3x-3
已知xy=8满足x²y-xy²-x+y=56,求x²+y²
1-x²+2xy-y²
3x²-4xy+y²
x²+y²+4x-8y+20=0,求分式x²-y²/xy的值
x²+y²+4x-8y+20=0,求(x²-y²)÷xy的解
计算:(1).(-2xy²)*(3x²y)²
x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy
已知x²y²+x²+y²=10xy-16 求x,y
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1.(x+y)²-4xy=( )²
因式分解:m³-2m²-4m+8;x²-2xy+y²-9
xy²/(x²y-y) × x²/(x²+x)=