已知cos(π/6-α)=m(|m|≤1),求cos(5π/6+α),sin(2π/3-α)的值
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已知cos(π/6-α)=m(|m|≤1),求cos(5π/6+α),sin(2π/3-α)的值
![已知cos(π/6-α)=m(|m|≤1),求cos(5π/6+α),sin(2π/3-α)的值](/uploads/image/z/18863842-58-2.jpg?t=%E5%B7%B2%E7%9F%A5cos%28%CF%80%2F6-%CE%B1%29%3Dm%28%7Cm%7C%E2%89%A41%29%2C%E6%B1%82cos%285%CF%80%2F6%2B%CE%B1%29%2Csin%282%CF%80%2F3-%CE%B1%29%E7%9A%84%E5%80%BC)
∵cos(π/6-α)=m(|m|≤1),
∴cos(5π/6+α)
=cos[π-(π/6-α)]
=-cos(π/6-α)
=-m
sin(2π/3-α)
=sin[π/2+(π/6-α)]
=cos(π/6-α)
=m
∴cos(5π/6+α)
=cos[π-(π/6-α)]
=-cos(π/6-α)
=-m
sin(2π/3-α)
=sin[π/2+(π/6-α)]
=cos(π/6-α)
=m
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