cos²45°-1/cos60°+1/tan45°+cos²30°+sin²45°
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/01 06:59:55
cos²45°-1/cos60°+1/tan45°+cos²30°+sin²45°
![cos²45°-1/cos60°+1/tan45°+cos²30°+sin²45°](/uploads/image/z/18856583-71-3.jpg?t=cos%26%23178%3B45%C2%B0-1%2Fcos60%C2%B0%2B1%2Ftan45%C2%B0%2Bcos%26%23178%3B30%C2%B0%2Bsin%26%23178%3B45%C2%B0)
原式=(√2/2)^2-1/(1/2)+1/1+(√2/2)^2
=(1/2)-2+1+(1/2)
=1-2+1
=0
望采纳,谢谢
=(1/2)-2+1+(1/2)
=1-2+1
=0
望采纳,谢谢
tan²30°+cos²30°-sin²45°tan45°
计算:sin²30°+cos²45°+根号2sin60°×tan45°
计算:(1)根号2sin45°+cos²60°-根号3tan60°+sin30°·tan45°
sin平方120°+cos180°+tan45°-cos平方(-330°)+sin(-210°)
计算 sin30°+cos²60°-tan45°-根号3*tan30°
计算:sin30°+cos60°+tan45°=______.
计算:sin260°+cos60°-tan45°=______.
化简:tan45°+sin420°×1/tan(-60°)+1/2(sin平方15°+cos平方15°)
√(cos 60°-1)²+2√cot 45°-sin 60°+|sin 30°-1|=?
/1-根号2/-(tan45°-1/2011)0次方+cos60°×(1/2)12次方+根号18求解答
(cos 45°-sin 30°)/(cos 45°+sin 30°)
tan30° sin30° cos30° tan60° sin60° cos60° tan45°