用可逆线性变换化下列二次型为标准形f(x1,x2,x3)=x1^2+2x2^2+5x3^2+2x1x2+2x2x3+6x
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用可逆线性变换化下列二次型为标准形f(x1,x2,x3)=x1^2+2x2^2+5x3^2+2x1x2+2x2x3+6x2x3
![用可逆线性变换化下列二次型为标准形f(x1,x2,x3)=x1^2+2x2^2+5x3^2+2x1x2+2x2x3+6x](/uploads/image/z/18766180-28-0.jpg?t=%E7%94%A8%E5%8F%AF%E9%80%86%E7%BA%BF%E6%80%A7%E5%8F%98%E6%8D%A2%E5%8C%96%E4%B8%8B%E5%88%97%E4%BA%8C%E6%AC%A1%E5%9E%8B%E4%B8%BA%E6%A0%87%E5%87%86%E5%BD%A2f%28x1%2Cx2%2Cx3%29%3Dx1%5E2%2B2x2%5E2%2B5x3%5E2%2B2x1x2%2B2x2x3%2B6x)
f(x1,x2,x3)=x1^2+2x2^2+5x3^2+2x1x2+2x1x3+6x2x3
= (x1+x2+x3)^2+x2^2+4x3^2+4x2x3
= (x1+x2+x3)^2+(x2+2x3)^2
= y1^2+y2^2
令 C=
1 1 1
0 1 2
0 0 1
则 Y=CX
= (x1+x2+x3)^2+x2^2+4x3^2+4x2x3
= (x1+x2+x3)^2+(x2+2x3)^2
= y1^2+y2^2
令 C=
1 1 1
0 1 2
0 0 1
则 Y=CX
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