╭13x+5y+9z=9.25 由{ 怎样得出x+y+z=?并写出结果!╰2x+4y+3z=3.2
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/04 01:38:29
╭13x+5y+9z=9.25 由{ 怎样得出x+y+z=?并写出结果!╰2x+4y+3z=3.2
![╭13x+5y+9z=9.25 由{ 怎样得出x+y+z=?并写出结果!╰2x+4y+3z=3.2](/uploads/image/z/18666284-68-4.jpg?t=%E2%95%AD13x%2B5y%2B9z%3D9.25+%E7%94%B1%7B+%E6%80%8E%E6%A0%B7%E5%BE%97%E5%87%BAx%2By%2Bz%3D%3F%E5%B9%B6%E5%86%99%E5%87%BA%E7%BB%93%E6%9E%9C%21%E2%95%B02x%2B4y%2B3z%3D3.2)
2x+4y+3z=3.2……(1)
13x+5y+9z=9.25……(2)
(2)-(1)*3得
7x-7y=-0.35
x=y-0.05……(3)
将(3)代入(1)得
z=1.1-2y
所以x+y+z=y-0.05+y+1.1-2y=1.05
13x+5y+9z=9.25……(2)
(2)-(1)*3得
7x-7y=-0.35
x=y-0.05……(3)
将(3)代入(1)得
z=1.1-2y
所以x+y+z=y-0.05+y+1.1-2y=1.05
x/2=y/3=z/5 x+3y-z/x-3y+z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(x+y-z)(x-y+z)=
3道高数题,1,函数F(x,y,z)=(e^x) * y * (z^2) ,其中z=z(x,y)是由x+y+z+xyz=
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
已知方程组{4x-3y-6z=0 x+2y-7z=0 且z≠0,则(x+y+3z)÷(4x-y-5z)=?结果和思路!
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
2x+5y+4z=0,3x+y-7z=0,则x+y-z=?
解方程组:x+y+z=4,x+y+2z=5,3x+y-z=6