1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^2

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/07/29 04:35:09

1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^2
2、xy（xy+1）+(xy+3)-2(x+y+1/2)-(x+y-1)^2
第二道题如果答案是(x+1）（y+1）（xy+x+y-1）就不用要过程了.
有答案保证+分

1、4(2x^2-x+1)(x^2+3-2x)-(3x^2-3x+4)^2
=4(2x^2-x+1)(x^2-2x+3)-[(2x^2-x+1)+(x^2-2x+3)]^2
=4(2x^2-x+1)(x^2-2x+3)-(2x^2-x+1)^2-2(2x^2-x+1)(x^2-2x+3)-(x^2-2x+3)^2
=-(2x^2-x+1)^2+2(2x^2-x+1)(x^2-2x+3)-(x^2-2x+3)^2
=-[(2x^2-x+1)^2-2(2x^2-x+1)(x^2-2x+3)-(x^2-2x+3)^2]
=-[(2x^2-x+1)-(x^2-2x+3)^2]^2
=-(x^2+x-2)^2
=-(x-1)^2(x+2)^2
2、xy（xy+1）+(xy+3)-2(x+y+1/2)-(x+y-1)^2
=x^2y^2+xy+xy+3-2(x+y)-1-(x+y)^2+2(x+y)-1
=x^2y^2+2xy+1-(x+y)^2
=(xy+1)^2-(x+y)^2
=(xy+1+x+y)(xy+1-x-y)
=(x+1)(y+1)(x-1)(y-1)

x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| x(2-1/x)+x/(x^2-2x)÷(3-x)/(x^2-4) x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 |x^2-3x-4|>x+1 (x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3 x-1)(X-2)(x-3)...(x-50)+x(x-2)(X-3)...(X-50)+...+x(x-1)(x-2) 约分 (X的平方+4x+3)(2x-x)^/(X^+X)(X^+X-6), x^4-x^3-2x^2+3x-1 x^4+x^3+2x^2+x+1 (x-1)^3(x+1)（x-2）/(x+4)