设x>=0,f(x)=x-1-ln^2x+2alnx(x.0).(1)令F(x)=xf'(x),讨论F(x)在(0,+无
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设x>=0,f(x)=x-1-ln^2x+2alnx(x.0).(1)令F(x)=xf'(x),讨论F(x)在(0,+无穷)内的单调性并求极值;(2)
![设x>=0,f(x)=x-1-ln^2x+2alnx(x.0).(1)令F(x)=xf'(x),讨论F(x)在(0,+无](/uploads/image/z/18591520-40-0.jpg?t=%E8%AE%BEx%3E%3D0%2Cf%28x%29%3Dx-1-ln%5E2x%2B2alnx%28x.0%29.%281%29%E4%BB%A4F%EF%BC%88x%29%3Dxf%27%28x%29%2C%E8%AE%A8%E8%AE%BAF%EF%BC%88x%29%E5%9C%A8%EF%BC%880%2C%2B%E6%97%A0)
f'(x)=1-2lnx/x+2a/x
F(X)=xf'(x)=x-2lnx+2a
F'(X)=1-2/x
讨论 x∈(0,2) F'(X)
F(X)=xf'(x)=x-2lnx+2a
F'(X)=1-2/x
讨论 x∈(0,2) F'(X)
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