3(a³-a²+1/2ab²)-1/2(6a³+4a²b+3ab&su
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/07/07 17:06:14
3(a³-a²+1/2ab²)-1/2(6a³+4a²b+3ab²)
![3(a³-a²+1/2ab²)-1/2(6a³+4a²b+3ab&su](/uploads/image/z/18564802-34-2.jpg?t=3%EF%BC%88a%26sup3%3B-a%26sup2%3B%EF%BC%8B1%EF%BC%8F2ab%26sup2%3B%EF%BC%89%EF%BC%8D1%EF%BC%8F2%EF%BC%886a%26sup3%3B%EF%BC%8B4a%26sup2%3Bb%EF%BC%8B3ab%26su)
3(a³-a²+1/2ab²)-1/2(6a³+4a²b+3ab²)
=3a³-3a²+3/2ab²-3a³-2a²b-3/2ab²
=-3a²-2a²b
=-a²(3+2b)
=3a³-3a²+3/2ab²-3a³-2a²b-3/2ab²
=-3a²-2a²b
=-a²(3+2b)
3x³+2x-5,4x²-4x-1,a³-3a²b+3ab²-b&su
若M=a³-3a²b+ab²,N=a³+1-2ab²,则2a³
3ab²+6a²b+3a³
因式分解的题(a²+7a+2)² -16 2a³b-4a²b²+2ab
因式分解 1.a³+3a²b+3ab²+b³ 2.a³+6a²
计算:1】—(2ab)³+3ab x a²b²2】(—2x³)² x
先化简再求值:(2ab²\a+b)³÷(ab²\a²-b²)²
3a-3b/10ab*25a²b³/a²-b² x²-4y²
已知:a+b=1,求a³+b³+3ab²+3a²b的值.
已知ab=3,求(2a³b²-3a²b+4a)×(-2b)的值
1、若a+b=3,ab=-2,求a³+a²b+ab²+b³的值。
已知a+b=1,ab=3の16,求代数式a³b-2a²b²=ab³的值