因式分解(x+1)(x-2)(x-3)(x-6)+20

来源：学生作业帮编辑：搜搜做题作业网作业帮分类：数学作业时间：2024/07/10 14:17:33

=[(x+1)(x-6)][(x-2)(x-3)]+20
=[(x²-5x)-6][(x²-5x)+6]+20
=(x²-5x)²-36+20
=(x²-5x)²-16
=(x²-5x+4)(x²-5x-4)
=(x-1)(x-4)(x²-5x-4)

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