x+2y+3z=1,x-y+4z=0,x+3y+2z=2拜托了各位
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x+2y+3z=1,x-y+4z=0,x+3y+2z=2拜托了各位
解方程组
解方程组
![x+2y+3z=1,x-y+4z=0,x+3y+2z=2拜托了各位](/uploads/image/z/18558260-44-0.jpg?t=x%2B2y%2B3z%3D1%2Cx-y%2B4z%3D0%2Cx%2B3y%2B2z%3D2%E6%8B%9C%E6%89%98%E4%BA%86%E5%90%84%E4%BD%8D)
x+2y+3z=1 ① x-y+4z=0 ② x+3y+2z=2 ③ ①-②得3y-z=1 ④ ①-③得-y+z=-1 ⑤ ④+⑤得y=0 代入⑤得z=-1 代入①得x=4
已知x/2=y/3=z/4且xyz不等于0,求2x+3y-z/x-3y+z拜托各位了 3Q
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x/2=y/3=z/5 x+3y-z/x-3y+z
{x+y+z=4 {2y+z=0 {3x+2y-4z=-1
若x-2y+4z=1,x+3y-7z=0,则y:z=?
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
2x-2y+z=0 2x+y-z=1 x+3y-2z=1
x+y+z=4 x-2y+z=-2 x+2y+3z=0求解
{2x-2y+z=0,2x+y-z+1,x+3y-2z=1
x+y+z=2 4x+2y+z=4 2x+3y+z=1