大一数学求极限
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大一数学求极限
![](http://img.wesiedu.com/upload/a/12/a127fac16e97856d03f2765174d667b7.jpg)
![](http://img.wesiedu.com/upload/a/12/a127fac16e97856d03f2765174d667b7.jpg)
![大一数学求极限](/uploads/image/z/18440723-11-3.jpg?t=%E5%A4%A7%E4%B8%80%E6%95%B0%E5%AD%A6%E6%B1%82%E6%9E%81%E9%99%90)
原式=limx→0 (e^2x-1-2x)/[x(e^2x-1)]
=limx→0 (e^2x-1-2x)/(x*2x) (e^2x-1~2x)
=limx→0 (2*e^2x-2)/4x (罗比塔法则)
=limx→0 (e^2x-1)/2x
=limx→0 2x/2x (e^2x-1~2x)
=1.
=limx→0 (e^2x-1-2x)/(x*2x) (e^2x-1~2x)
=limx→0 (2*e^2x-2)/4x (罗比塔法则)
=limx→0 (e^2x-1)/2x
=limx→0 2x/2x (e^2x-1~2x)
=1.