三元方程组(x+y+1)/(xy+x)=1/2(x+z+2)/(xz+2x)=1/3(y+z+3)/(y+1)(z+2)
来源:学生作业帮 编辑:搜搜做题作业网作业帮 分类:数学作业 时间:2024/08/04 03:09:45
三元方程组
(x+y+1)/(xy+x)=1/2
(x+z+2)/(xz+2x)=1/3
(y+z+3)/(y+1)(z+2)=1/4
(x+y+1)/(xy+x)=1/2
(x+z+2)/(xz+2x)=1/3
(y+z+3)/(y+1)(z+2)=1/4
![三元方程组(x+y+1)/(xy+x)=1/2(x+z+2)/(xz+2x)=1/3(y+z+3)/(y+1)(z+2)](/uploads/image/z/18303969-57-9.jpg?t=%E4%B8%89%E5%85%83%E6%96%B9%E7%A8%8B%E7%BB%84%EF%BC%88x%2By%2B1%29%2F%28xy%2Bx%29%3D1%2F2%28x%2Bz%2B2%29%2F%28xz%2B2x%29%3D1%2F3%28y%2Bz%2B3%29%2F%28y%2B1%29%28z%2B2%29)
设a=x,b=y+1,c=z+2,则方程组化为:
(a+b)/ab=1/2
(a+c)/ac=1/3
(b+c)/bc=1/4
即:
1/a+1/b=1/2
1/a+1/c=1/3
1/b+1/c=1/4
所以,
1/a+1/b+1/c=(1/2+1/3+1/4)/2=13/24
1/a=13/24-1/4=7/24
1/b=13/24-1/3=5/24
1/c=13/24-1/2=1/24
所以,
x=a=24/7
y+1=b=24/5,y=19/5
z+2=c=24,z=22
x=24/7,y=19/5,z=22
(a+b)/ab=1/2
(a+c)/ac=1/3
(b+c)/bc=1/4
即:
1/a+1/b=1/2
1/a+1/c=1/3
1/b+1/c=1/4
所以,
1/a+1/b+1/c=(1/2+1/3+1/4)/2=13/24
1/a=13/24-1/4=7/24
1/b=13/24-1/3=5/24
1/c=13/24-1/2=1/24
所以,
x=a=24/7
y+1=b=24/5,y=19/5
z+2=c=24,z=22
x=24/7,y=19/5,z=22
三元二次方程组(XY+X)/(X+Y+1)=2(XZ+2X)/(X+Z+2)=3(Y+1)(Z+2)/(Z+Y+3)=4
解三元一次方程组 x+y+z=26 x-y+xz=1 2x-y+z=18
解三元一次方程组x:y:z=1:2:3 x+y+z=36
三元一次方程组数学题x+2y+2z=33x+y-2z=72x+3y-2z=10x-y=2z-x=3y+z=-1x-y-z
解三元一次方程组x:y=2:1,2x-y=3z,x+y+z=20
如果1=xy/x+y,2=yz/y+z,3=xz/x+z,则x的值?
2x+y=4,x+3z=1,x+y+z=7解这个三元一次方程组
x-3=y-2=z-1,求x^2+y^2+z^2-xy-yz-xz的值
已知x+y+z=3,xy+yz+xz=-1,xyz=2,求x^2y^2+y^2z^2+x^2z^2
三元一次方程组求解!1) X+Y+Z= 1 X+Y+2Z=2 X+3Y+Z=3 2) X+Y+Z=1 X+Y+2Z=2
解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-
解三元一次方程组 1.{2x-y+z=1,3x+y-2z=2,x+2y-z=3 2.{3x-y+z=4,2x+3y-z=