(x-1分之x²+5x) - (x²-x分之2x²+4x)求解释
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(x-1分之x²+5x) - (x²-x分之2x²+4x)求解释
![(x-1分之x²+5x) - (x²-x分之2x²+4x)求解释](/uploads/image/z/18196530-42-0.jpg?t=%28x-1%E5%88%86%E4%B9%8Bx%26%23178%3B%2B5x%29+-+%28x%26%23178%3B-x%E5%88%86%E4%B9%8B2x%26%23178%3B%2B4x%29%E6%B1%82%E8%A7%A3%E9%87%8A)
(x-1分之x²+5x) - (x²-x分之2x²+4x)
=(x²+5x)/(x-1)-(2x+4)/(x-1)
=(x²+3x-4)/(x-1)
=(x+4)(x-1)/(x-1)
=x+4
=(x²+5x)/(x-1)-(2x+4)/(x-1)
=(x²+3x-4)/(x-1)
=(x+4)(x-1)/(x-1)
=x+4
x²-2x分之x+2-x²-4x+4分之x-1
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
(x-2分之3x-x+2分之x)乘x分之x²-4
(x-1分之2x - x+1分之x)×x分之x²-1=
x - x-1分之1=1 1-x分之1 - 2=1-x²分之3x-x² x-4分之7 - x-2分之
化简x-1分之x²+1-x分之x
x-1分之x² -x-1
先化简,再求值:(x²+2x分之x-2-x²+4x+4分之x-1)÷x+2分之x-4,其中x
(x²-4分之x+1-x+2分之2)除以x+2分之X-5
已知x分之x²-x+1=5,求x²分之x四次+x²+1的值
(x²-4x+4分之x²-4+x+2分之2-x)除以x-2分之x
化简:x+2分之x²+2x+1除以x-1分之x²-1-x+2分之x