设f(x)=1+x*2/1-x*2,求证:(1) f(-x)=f(x); (2) f(1/x)=-f(x)谢谢了,
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设f(x)=1+x*2/1-x*2,求证:(1) f(-x)=f(x); (2) f(1/x)=-f(x)谢谢了,
![设f(x)=1+x*2/1-x*2,求证:(1) f(-x)=f(x); (2) f(1/x)=-f(x)谢谢了,](/uploads/image/z/18183470-14-0.jpg?t=%E8%AE%BEf%28x%29%3D1%2Bx%2A2%2F1-x%2A2%2C%E6%B1%82%E8%AF%81%EF%BC%9A%281%29+f%28-x%29%3Df%28x%29%3B+%282%29+f%281%2Fx%29%3D-f%28x%29%E8%B0%A2%E8%B0%A2%E4%BA%86%2C)
是不是写错了 那里应该是X的平方而不是X乘以2吧 (1) f(-x)=1+(-x)^2/1-(-x)^2=1+x^2/1-x^2=f(x) (2) f(1/x)=1+(1/x^2)/1-(1/x^2)=x^2+1/x^2-1 -f(x)=-1-x^2/1-x^2=1+x^2/x^2-1 所以f(1/x)=-f(x)
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