(1/4)lgx(n+1)=1+lgxn 即:lgXn+1=lg10Xn即:Xn+1=10Xn,所以数列{Xn}为等比数
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(1/4)lgx(n+1)=1+lgxn 即:lgXn+1=lg10Xn即:Xn+1=10Xn,所以数列{Xn}为等比数列,公比为10 x1+
![(1/4)lgx(n+1)=1+lgxn 即:lgXn+1=lg10Xn即:Xn+1=10Xn,所以数列{Xn}为等比数](/uploads/image/z/18175760-8-0.jpg?t=%281%2F4%29lgx%EF%BC%88n%2B1%EF%BC%89%3D1%2Blgxn+%E5%8D%B3%EF%BC%9AlgXn%2B1%3Dlg10Xn%E5%8D%B3%EF%BC%9AXn%2B1%3D10Xn%2C%E6%89%80%E4%BB%A5%E6%95%B0%E5%88%97%7BXn%7D%E4%B8%BA%E7%AD%89%E6%AF%94%E6%95%B0)
lgxn+1=1+lgxn
lgxn+1=1+lgxn xn+1=10×xn即 =10
x1+x2+……+x100=100
x1+x1q+x1q2+……+x1q99=100
lg(x101+……+x200)
=lg(x1q100+……+x1q199)
=lg[q100(x1+……+x1q99)]
=102
lgxn+1=1+lgxn xn+1=10×xn即 =10
x1+x2+……+x100=100
x1+x1q+x1q2+……+x1q99=100
lg(x101+……+x200)
=lg(x1q100+……+x1q199)
=lg[q100(x1+……+x1q99)]
=102
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