已知x:y:z=2:3:4,且x+y+z=1/12,求xyz的值
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已知x:y:z=2:3:4,且x+y+z=1/12,求xyz的值
![已知x:y:z=2:3:4,且x+y+z=1/12,求xyz的值](/uploads/image/z/18112099-67-9.jpg?t=%E5%B7%B2%E7%9F%A5x%3Ay%3Az%3D2%3A3%3A4%2C%E4%B8%94x%2By%2Bz%3D1%2F12%2C%E6%B1%82xyz%E7%9A%84%E5%80%BC)
设 x=2t,y=3t,z=4t
2t+3t+4t=1/12
t=1/12/9=1/108
xyz=2*3*4*(1/108)³=1/52488
2t+3t+4t=1/12
t=1/12/9=1/108
xyz=2*3*4*(1/108)³=1/52488
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